+ /* If at end of pattern, accept immediately. */
+ if (!*pattern)
+ return 1;
+
+ /* If next character in pattern is known, optimize. */
+ if (*pattern != '?' && *pattern != '*') {
+ /*
+ * Look instances of the next character in
+ * pattern, and try to match starting from
+ * those.
+ */
+ for (; *s; s++)
+ if (*s == *pattern &&
+ match_pattern(s + 1, pattern + 1))
+ return 1;
+ /* Failed. */
+ return 0;
+ }
+ /*
+ * Move ahead one character at a time and try to
+ * match at each position.
+ */
+ for (; *s; s++)
+ if (match_pattern(s, pattern))
+ return 1;
+ /* Failed. */
+ return 0;
+ }
+ /*
+ * There must be at least one more character in the string.
+ * If we are at the end, fail.
+ */
+ if (!*s)
+ return 0;
+
+ /* Check if the next character of the string is acceptable. */
+ if (*pattern != '?' && *pattern != *s)
+ return 0;
+
+ /* Move to the next character, both in string and in pattern. */
+ s++;
+ pattern++;
+ }
+ /* NOTREACHED */
+}
+
+/*
+ * Tries to match the string against the
+ * comma-separated sequence of subpatterns (each possibly preceded by ! to
+ * indicate negation). Returns -1 if negation matches, 1 if there is
+ * a positive match, 0 if there is no match at all.
+ */
+
+int
+match_pattern_list(const char *string, const char *pattern, u_int len,
+ int dolower)
+{
+ char sub[1024];
+ int negated;
+ int got_positive;
+ u_int i, subi;
+
+ got_positive = 0;
+ for (i = 0; i < len;) {
+ /* Check if the subpattern is negated. */
+ if (pattern[i] == '!') {
+ negated = 1;
+ i++;
+ } else
+ negated = 0;
+
+ /*
+ * Extract the subpattern up to a comma or end. Convert the
+ * subpattern to lowercase.
+ */
+ for (subi = 0;
+ i < len && subi < sizeof(sub) - 1 && pattern[i] != ',';
+ subi++, i++)
+ sub[subi] = dolower && isupper(pattern[i]) ?
+ (char)tolower(pattern[i]) : pattern[i];
+ /* If subpattern too long, return failure (no match). */
+ if (subi >= sizeof(sub) - 1)
+ return 0;
+
+ /* If the subpattern was terminated by a comma, skip the comma. */
+ if (i < len && pattern[i] == ',')
+ i++;
+
+ /* Null-terminate the subpattern. */
+ sub[subi] = '\0';
+
+ /* Try to match the subpattern against the string. */
+ if (match_pattern(string, sub)) {
+ if (negated)
+ return -1; /* Negative */
+ else
+ got_positive = 1; /* Positive */
+ }
+ }
+
+ /*
+ * Return success if got a positive match. If there was a negative
+ * match, we have already returned -1 and never get here.
+ */
+ return got_positive;
+}